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36x^2-92=53
We move all terms to the left:
36x^2-92-(53)=0
We add all the numbers together, and all the variables
36x^2-145=0
a = 36; b = 0; c = -145;
Δ = b2-4ac
Δ = 02-4·36·(-145)
Δ = 20880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20880}=\sqrt{144*145}=\sqrt{144}*\sqrt{145}=12\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{145}}{2*36}=\frac{0-12\sqrt{145}}{72} =-\frac{12\sqrt{145}}{72} =-\frac{\sqrt{145}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{145}}{2*36}=\frac{0+12\sqrt{145}}{72} =\frac{12\sqrt{145}}{72} =\frac{\sqrt{145}}{6} $
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